
1892 United States House of Representatives elections
House elections for the 53rd U.S. Congress

House elections for the 53rd U.S. Congress
The 1892 United States House of Representatives elections were held for the most part on November 8, 1892, with Oregon, Maine, and Vermont holding theirs early in either June or September. They coincided with the election of Grover Cleveland as president for the second, noncontinuous time, defeating incumbent Benjamin Harrison. Elections were held for 356 seats of the United States House of Representatives, representing 44 states, to serve in the 53rd United States Congress. They were the first elections after the reapportionment following the 1890 United States census, which increased the size of the House. Special elections were also held throughout the year. Despite the presidential results, Harrison's Republican Party regained some of the seats lost in 1890 to the Democratic Party, but was still in the minority. The Republican pickups were the result of several Republican-friendly Northern districts reverting to form after voting Democratic in the previous election cycle. The third...
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