1992 United States presidential election in Iowa
The 1992 United States presidential election in Iowa took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president. Iowa was won by Democratic governor Bill Clinton of Arkansas with 43.29% of the popular vote over incumbent Republican President George H. W. Bush's 37.27%, a victory margin of 6.01%. Independent businessman Ross Perot finished in third, with 18.71% of the popular vote. Clinton ultimately won the national vote, defeating incumbent president Bush and Perot. With a margin of victory of 6.02% for Clinton, the state voted 0.46% to the left of the nation at-large and became the closest to the national results. Despite this, Iowa was the only state that swung more Republican than it had been in 1988, swinging rightward by 4.2%. This was the first of six consecutive elections that Iowa did back the winner of the national popular vote, gave...
Read on Wikipedia · Image Inqvisitor, CC BY-SA 3.0
Open boosters, collect cards and trade them. Free to play.
Play for free