1992 United States presidential election in Kansas

Common card · No. 469134

The 1992 United States presidential election in Kansas took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for president and vice president. Kansas was won by incumbent President George H. W. Bush (R-Texas) with 38.88% of the popular vote over Governor Bill Clinton (D-Arkansas) with 33.74%. Businessman Ross Perot (I-Texas) finished in third, with 26.99% of the popular vote. Kansas was surprisingly close, likely because Ross Perot split the vote. Had Clinton won in Kansas, it would have been a major upset victory. Notably, ABC News called Kansas for Clinton incorrectly before rescinding the call. Clinton ultimately won the national vote, defeating incumbent President Bush and Perot. As of the 2024 presidential election, this is the last election in which Kansas was decided by single digits and the last time that Ellis County, Cherokee County, Leavenworth County, Labette...

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