1988 United States presidential election in Iowa
The 1988 United States presidential election in Iowa took place on November 8, 1988, as part of the 1988 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for president and vice president. Iowa was won by Democratic governor Michael Dukakis of Massachusetts with 54.71% of the popular vote over Republican Vice President George H. W. Bush's 44.50%, a victory margin of 10.21%, which made Iowa exactly 18% more Democratic than the nation-at-large. A major reason why it voted so Democratic compared to the rest of the nation was the 1980s farm crisis. This made it one of 10 states (along with the District of Columbia) to vote for Dukakis, while Bush won a convincing electoral victory nationwide. Bush became the first Republican to ever win the presidency without carrying Iowa, a feat that would only be repeated once more, when his son George W. Bush lost the state in 2000 but won the national election by extremely narrow margins...
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